First order torsion-first field equation: structure and interpretation

If torsion-first is going to mean anything operational, the action has to be written in variables you are actually allowed to vary. The only thing you can safely push through an Euler-Lagrange variation is a covariant field on $Y.$ That field is the augmented torsion $T.$

Nusa

March 22, 2026 · 4 min read

Definitions / Notation used

Define:

$$ \Upsilon_\omega := \bullet_\varepsilon(F_B) - \kappa_1 T $$

$$ I_1(\omega) := \int_Y \langle T, *_Y \Upsilon_\omega \rangle $$

What this action is really doing

$I_1$ is a torsion swervature pairing. It is constructed so it lives in the same bundle as $T$, allowing a gauge-covariant pairing.

The action is written in terms of:

  1. a covariant 1-form $T$
  2. a covariant form $\bullet_\varepsilon(F_B)$

both valued in $\mathrm{ad}(P_H)$, paired via: $$ \langle \cdot , \cdot \rangle \quad \text{and} \quad *_Y $$

Torsion first principle: the field is $T$, not the connection.

Variation sketch why $\Upsilon_\omega = 0$

Connections are affine, so vary the translation part:

$$ \omega_s = (\varepsilon, \eta + s \alpha), \quad \alpha \in \Omega^1(Y, \mathrm{ad}(P_H)) $$

Then: $T_s = T + s \alpha$ and $\delta T = \alpha$.

Since $B_\omega$ depends only on $\varepsilon$:

$$ \delta F_B = 0 $$

Thus: $$ \delta \Upsilon_\omega = -\kappa_1 \alpha $$

Step 2: Vary the action#

$$ \delta I_1 = \int_Y \left( \langle \delta T, *_Y \Upsilon_\omega \rangle + \langle T, *_Y \delta \Upsilon_\omega \rangle \right) $$

Insert: $$ \delta T = \alpha, \quad \delta \Upsilon_\omega = -\kappa_1 \alpha $$

$$ \delta I_1 = \int_Y \left( \langle \alpha, *_Y \Upsilon_\omega \rangle - \kappa_1 \langle T, *_Y \alpha \rangle \right) $$

With the normalization convention: $$ \frac{\delta}{\delta T} \langle T, *_Y T \rangle = *_Y T $$

the terms combine into: $$ \delta I_1 = \int_Y \langle \alpha, *_Y (\bullet_\varepsilon(F_B) - \kappa_1 T) \rangle $$

$$ \delta I_1 = \int_Y \langle \alpha, *_Y \Upsilon_\omega \rangle $$

Since $\alpha$ is arbitrary: $$ \Upsilon_\omega = 0 $$

Technical lemma normalization

Define: $$ Q(T) := \int_Y \langle T, *_Y T \rangle $$

Then: $$ \delta Q(T)[\alpha] = \int_Y \langle \alpha, *_Y T \rangle $$

No factor of 2 appears due to polarization normalization.

What about varying $\varepsilon$

$\varepsilon$ enters in:

The resulting variation yields a compatibility condition: a Bianchi-type identity linking curvature and torsion through $\bullet_\varepsilon$ and $\Theta_E$.

No Ricci-type contraction appears.

Assumptions vs consequences

Assumptions#

Consequences#

$$ \Upsilon_\omega = 0 \quad \Rightarrow \quad \bullet_\varepsilon(F_B) = \kappa_1 T $$

Why this matters

This is the point where the construction becomes a field theory on $Y$. The dynamics are written entirely in covariant objects.

Recovering GR will mean showing that $\bullet_\varepsilon(F_B)$ reduces to the Einstein contraction in a controlled regime.

Key takeaway

The action is built from torsion $T$, and its stationary points satisfy: $\Upsilon_\omega = 0 $

Technical takeaway

$$ I_1(\omega) = \int_Y \langle T, *_Y (\bullet_\varepsilon(F_B) - \kappa_1 T) \rangle \quad \Rightarrow \quad \Upsilon_\omega = 0 $$

#action#euler-lagrange#geometric unity#gu#physics#science#torsion
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Written by

Nusa

Frontend dev. Working on Decent Newsroom - a client for collaborative long-form publishing.

nusa@gitcitadel.com

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